(a)Fig. 2.1 shows an electric motor lifting a load. The load, of weight 5.0 N, is raised through a vertical height of 3.5 m at a constant speed. The efficiency of the electric motor is 0.65 (65%). Calculate the increase in gravitational potential energy of the load.
2016 · M/J · 5054/22 | Q2
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(b)(i)Fig. 2.1 shows an electric motor lifting a load. The load, of weight 5.0 N, is raised through a vertical height of 3.5 m at a constant speed. The efficiency of the electric motor is 0.65 (65%). State the formula that relates efficiency, energy input and useful energy output.
(b)(ii)Fig. 2.1 shows an electric motor lifting a load. The load, of weight 5.0 N, is raised through a vertical height of 3.5 m at a constant speed. The efficiency of the electric motor is 0.65 (65%). Calculate the energy input to the motor.
(c)Fig. 2.1 shows an electric motor lifting a load. The load, of weight 5.0 N, is raised through a vertical height of 3.5 m at a constant speed. The efficiency of the electric motor is 0.65 (65%). Suggest one reason why the efficiency of the motor is less than 1.0 (100%).
5054/22/M/J/16Cambridge O Level Physics 5054 · May/June 2016 · Paper 2 variant 2 · Question 2