(a)(i)A load of mass M is fixed at the 5.0 cm mark of a metre rule, pivoted at the 50.0 cm mark, as shown in Fig. 3.1. A 50 g movable load balances it. Read both edges of the 50 g load in Fig. 3.2 and determine the position of its centre on the rule.
2024 · M/J · 5054/42 | Q3
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(a)(ii)Using your centre position from 3(a)(i), calculate distance d from the centre of the 50 g load to the 50.0 cm pivot in Fig. 3.1. Record d in Table 3.1.
(a)(iii)Calculate 1000 / d from your 3(a)(ii) distance in cm and record it to three significant figures in the first row of Table 3.1, in cm⁻¹.
(b)It is difficult to balance the metre rule in Fig. 3.1 exactly. Describe a technique to make distance d as accurate as possible.
(c)Plot m / g on the y-axis against 1000 / d in cm⁻¹ on the x-axis on Fig. 3.3 and draw a straight line of best fit. Table 3.1 prints (m / g, d / cm, 1000 / d in cm⁻¹): (50, blank, blank), (60, 37.7, 26.5), (70, 32.3, 31.0), (80, 28.2, 35.5), (90, 25.3, 39.5), (100, 22.2, 45.0). Fill the 50 g row from your earlier answers. Axes need not begin at zero.
(d)(i)Calculate the gradient G of your straight best-fit line on Fig. 3.3. Show working and mark on your graph the values used.
(d)(ii)Use your own gradient G from 3(d)(i) and M = 22.2 × G to determine the fixed load mass M, in g.
(e)Explain why the Fig. 3.1 balancing method is unsuitable if the movable load has mass m = 40 g.
5054/42/M/J/24Cambridge O Level Physics 5054 · May/June 2024 · Paper 4 variant 2 · Question 3